Re: Help for solving this Integrate[Sqrt[t*(1-t)* (t-z),{t,0,z} ] NEW!!!!
- To: mathgroup at smc.vnet.net
- Subject: [mg112837] Re: Help for solving this Integrate[Sqrt[t*(1-t)* (t-z),{t,0,z} ] NEW!!!!
- From: Curtis Osterhoudt <cfo at lanl.gov>
- Date: Sat, 2 Oct 2010 05:46:44 -0400 (EDT)
In[13]:= Integrate[Sqrt[t*(1 - z)*(t - z)], {t, 0, z}, Assumptions -> z > 0] Out[13]= 1/8 \[Pi] Sqrt[-1 + z] z^2 It helped me a great deal to plot both the integral and the answers (especially the integral) vs. t, with various values of z. Then I recognized the integrand can be cast into a slightly different form: Integrate[Sqrt[-1*((t - z/2)^2 - z^2/4)], {t, 0, z}, Assumptions -> z > 0 && 0 <= t <= z] The integral gives (\[Pi] z^2)/8 which is simply the area of half a circle with radius z/2; the circles are obvious if you plot the integrand. They're later scaled by the Sqrt[z-1] factor. On Friday, October 01, 2010 03:41:39 Hugo wrote: > Could any body help me to solve the following integral in > mathematica? > > Integrate[sqrt[t * (1-z)*(t-z),{t,0,z}]; t and z are reals; z>0 > > I did make a mistake posting the wrong equation yesterday, I apologize > for that. > > Any help would be appreciate, > > Hugo > > -- ================================== Curtis Osterhoudt cfo at remove_this.lanl.and_this.gov ==================================