Re: A list based table join?

• To: mathgroup at smc.vnet.net
• Subject: [mg112965] Re: A list based table join?
• From: Albert Retey <awnl at gmx-topmail.de>
• Date: Fri, 8 Oct 2010 04:49:20 -0400 (EDT)
• References: <i8jteq\$aco\$1@smc.vnet.net>

```Am 07.10.2010 09:39, schrieb Leo Ditolaghi:
> Hi all,
>
> (noob Mathematica question:)
>
> If I have two lists, how do I determine the indices at which the 1st list
> elements are matched by the elements of the second, and then use these
> matching indices to extract corresponding columns in the 1st list (sort of a
> simulated database join)? I.e.,
>
> x = {{"hello", 27},
> {"bye", 30},
> {"hello", 54},
> {"seeya", 100},
> {"hi", 9}}
>
> y = {"hello", "hi"}
>
> where x is the source table, and y is the select criteria (so to speak.)
>
> I wish to produce z, where y defines which elements of x to extract:
>
> z = {27,54,9}
>
> I know this should be easy and elegant, but I am going in circles
> with list functions.

These are short, might qualify as "elegant", I'm not so sure about easy
and I'm sure that there are more efficient ways to to this when x or y
get large. On the other hand: "premature optimization is the root of all
evil"

Cases[x, {Alternatives @@ y, val_} :> val]

Select[x, MemberQ[y, #[[1]]] &][[All, 2]]

hth,

albert

```

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