Re: Replacement in a held function

*To*: mathgroup at smc.vnet.net*Subject*: [mg113326] Re: Replacement in a held function*From*: "István Zachar" <replicatorzed at gmail.com>*Date*: Sat, 23 Oct 2010 07:08:19 -0400 (EDT)*References*: <i9r81q$hq2$1@smc.vnet.net> <35a9220c-0de4-400e-be47-c739b715101c@u10g2000yqk.googlegroups.com>

Dear Valeri, this is of course the trivial solution, though as I said, I cannot modify the signature of func, so I HAVE to rely on some pre-evaluation replacement method. bests Istvan On 2010.10.22. 9:14, Valeri Astanoff wrote: > On 22 oct, 07:39, István Zachar<z... at freemail.hu> wrote: >> Dear Group, >> >> How can the following toy example be modified to yield {1, 2, 3} >> instead of {t, t, t}? Suppose func, t and list are given parameters >> that cannot be changed, so I want to solve it with some kind of >> argument-replacement-inside-the-loop method. Thus I'm looking for a >> solution which only manipulates the internals of Do. If it is possible >> at all. >> >> In[104]:= list = {}; >> func := AppendTo[list, t]; >> Do[func /. {t -> i}, {i, 3}]; >> list >> >> Out[107]= {t, t, t} > Why not this way : > > list = {}; > func[t_] := AppendTo[list, t]; > Do[func[i], {i, 3}]; > list > > {1, 2, 3} > > >