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Re: FunctionQ?
*To*: mathgroup at smc.vnet.net
*Subject*: [mg113311] Re: FunctionQ?
*From*: Pierre Albarede <pa.news at free.fr>
*Date*: Sat, 23 Oct 2010 07:05:28 -0400 (EDT)
*References*: <i9r7vd$hoo$1@smc.vnet.net>
On Oct 22, 7:37 am, Sam Takoy <sam.ta... at yahoo.com> wrote:
> How does one tell whether a variable is a function?
> More specifically, how does one tell whether a variable is a function of
> two arguments?
If an expression has the head Function, for example, Function[2#] or
2#&, then it is a function.
But the converse is not true. A lot of functions do not have the head
Function, for example, Head@Sin -> Symbol.
Any symbol with no rules can be considered as a function of any number
of argument, for example, ClearAll@f1; f1[x] is a valid expression.
You can check if some expression is a function of 2 arguments by
trying :
Check[Sin[x, y], "not a function of 2", Sin::argx]
->
Sin::argx: Sin called with 2 arguments; 1 argument is expected. >>
not a function of 2
Check[Log[x, y], "not a function of 2", Sin::argx]
->
Log[y]/Log[x]
Log can also be a function of 1.
> Finally, how does one tell whether a variable is a function of two
> arguments that returns an array?
I have already explained the first part of the question. Now, how to
tell whether an expresion is an array ? I guess you mean array =
matrix. You can check if Transpose works :
Check[Transpose@Array[f1, {4, 5}];, "not a matrix"]
Check[Transpose@{{x}, {x, y}};, "not a matrix"]
Putting those ideas into general programs would require many
programming skils but it may be a waste of time. It is not the
philosophy of Mathematica to check types carefully, because
Mathematica is interpreted and very tolerant with respect to types. A
function will accomodate any type of argument, provided what you are
doing with it makes sense. If not, you will see a flow of error
messages.
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