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Re: NDSolve grid
*To*: mathgroup at smc.vnet.net
*Subject*: [mg113360] Re: NDSolve grid
*From*: schochet123 <schochet123 at gmail.com>
*Date*: Mon, 25 Oct 2010 06:40:56 -0400 (EDT)
*References*: <i9m83u$jhm$1@smc.vnet.net>
On Oct 20, 10:09 am, pratip <pratip.chakrabo... at gmail.com> wrote:
> Here is the code that tries to recover the data about the grid where a
> PDE is solved in Mathematica.
> {sol, steps} =
> Reap[NDSolve[{D[u[t, x, y], t, t] ==
> D[u[t, x, y], x, x] + D[u[t, x, y], y, y] + Sin[u[t, x, y]],
> u[t, -L, y] == u[t, L, y], u[t, x, -L] == u[t, x, L],
> u[0, x, y] == Exp[-(x^2 + y^2)],
> Derivative[1, 0, 0][u][0, x, y] == 0},
> u, {t, 0, L/2}, {x, -L, L}, {y, -L, L},
> StepMonitor :> Sow[{x, y}]]];
>
> I want to see the 2D grid that NDSolve use to discretize the PDE. Is
> it possible to do?
I found the following trick in the source code of the NDSolveUtilities
package:
sol=NDSolve[whatever]
ifun=u /.sol[[1]] (* where u is the name of (one of ) the dependent
variable(s) *)
(* This should return an InterpolatingFunction
object *)
ifun["Coordinates"]
(* returns list of lists of coordinates for each independent variable
*)
(* e.g. {{t0,t1, ... tf},{x1,x2,...,xf}} *)
Steve
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