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Re: broadcasting of Equal ? (newbie question)

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  • Subject: [mg118177] Re: broadcasting of Equal ? (newbie question)
  • From: Bob Hanlon <hanlonr at cox.net>
  • Date: Fri, 15 Apr 2011 03:57:26 -0400 (EDT)

More generally,

Solve[{x + y - 1, 2 x + y - 2} == {a, a}, {x, y}] ==
 
 Solve[{x + y - 1, 2 x + y - 2} == a, {x, y}]

True

Perhaps it automatically uses Thread

 Thread[{x + y - 1, 2 x + y - 2} == a]

{-1 + x + y == a, -2 + 2 x + y == a}

 Thread[{x + y - 1, 2 x + y - 2} == {a, b}]

{-1 + x + y == a, -2 + 2 x + y == b}


Bob Hanlon

---- Alan <alan.isaac at gmail.com> wrote: 

=============
I noticed that e.g.
Solve[{x + y - 1, 2 x + y - 2} == {0, 0}, {x, y}]
can be written as
Solve[{x + y - 1, 2 x + y - 2} == 0, {x, y}]
but I cannot find the rule that allows this.
(E.g., I do not find it in the help for Equal
or the help for Solve.)

Can you point me to it?

Thanks,
Alan



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