Re: Simplify results
- To: mathgroup at smc.vnet.net
- Subject: [mg118285] Re: Simplify results
- From: "Sjoerd C. de Vries" <sjoerd.c.devries at gmail.com>
- Date: Wed, 20 Apr 2011 04:27:50 -0400 (EDT)
- References: <iojpot$i4q$1@smc.vnet.net>
They are the same. Both the nominator and denominator are sign- reversed. Cheers -- Sjoerd More Mathematica questions answered at StackOverflow http://stackoverflow.com/questions/tagged/mathematica On Apr 19, 12:56 pm, "Berthold Hamburger" <b-hambur... at artinso.com> wrote: > Hi, > > This might be a silly question, so please bear with me, but I have been > scratching my head about it for some time now. > > Is there a particular reason why Mathematica (8.01) simplifies the following > fraction reversing the signs in the result: > > IN: > > Simplify[(8a^2b^3(c^2+1)^4-6a^3b^2(c^2+1)^3+14a^4b > (c^2+1)^2)/(4a^3b^2(c^2+1)^2-10a^4b^3(c^2+1)^3)] > > OUT: > > (-7 a^2+3 a b (1+c^2)-4 b^2 (1+c^2)^2)/(a b (-2+5 a b (1+c^2))) > > Reducing the fraction by hand gives me: > > (7 a^2-3 a b (1+c^2)+4 b^2 (1+c^2)^2)/(a b (2-5 a b (1+c^2))) > > Thanks > > Berthold > > -- > > Berthold Hamburger - Cellist/Spain > > Email: beha... at artinso.com > > http://www.artinso.com > > http://www.astronomy.artinso.com