Re: Complex diagram
- To: mathgroup at smc.vnet.net
- Subject: [mg123476] Re: Complex diagram
- From: Murray Eisenberg <murray at math.umass.edu>
- Date: Thu, 8 Dec 2011 05:26:41 -0500 (EST)
- Delivered-to: l-mathgroup@mail-archive0.wolfram.com
- References: <201112080022.TAA12699@smc.vnet.net>
- Reply-to: murray at math.umass.edu
I my original reply (not yet posted by the moderator) to MathGroup, I make a mistake in the code for using Presentations that was supposed to show the unit circle and its image. That code showed another circle as image, which of course is wrong. Instead of using ComplexCircle, I need to use ComplexCurve: <<Presentations` f[z_] := 2 Re[z] + 3 Im[z] I domain = {DrawCartesianMap[z, {z, -(1 + I), 1 + I}], Red, ComplexCurve[Exp[I t], {t, 0, 2 Pi}]}; image = domain // ComplexMap[f]; GraphicsRow[{Draw2D[{domain}, Axes -> True], Draw2D[{image}, Axes -> True]}] The reason is that the Presentation function ComplexMap[f] merely applies the complex function f to the center of the circle ComplexCircle[0,1] and then forms another circle with that image point and the same radius as the original one. For ComplexCurve[...], on the other hand, ComplexMap[f] samples points on the curve -- here the unit circle -- and calculates the image of each = of those points. On 12/7/11 7:22 PM, =E9=81=93 =E5=8E=9A wrote: > Can we draw complex funtions's diagram in Mathematica? > > For example, draw the picture of z=2*x+I*3*y > -- Murray Eisenberg murray at math.umass.edu Mathematics & Statistics Dept. Lederle Graduate Research Tower phone 413 549-1020 (H) University of Massachusetts 413 545-2859 (W) 710 North Pleasant Street fax 413 545-1801 Amherst, MA 01003-9305
- References:
- Complex diagram
- From: é å <shlwell1988@gmail.com>
- Complex diagram