       Re: Replace elements in a matrix

• To: mathgroup at smc.vnet.net
• Subject: [mg116445] Re: Replace elements in a matrix
• Date: Wed, 16 Feb 2011 04:32:15 -0500 (EST)

```A solution based on Transpose and ReplaceAll

In:= a = {{0, 1}, {1, 2}}; b = {{1, 3}, {2, 5}};

Transpose[{a, b}, {3, 1, 2}]

% /. {{1, x_Integer} :> x, {x_Integer, _Integer} :> x}

Out= {{{0, 1}, {1, 3}}, {{1, 2}, {2, 5}}}
Out= {{0, 3}, {2, 2}}

2011/2/15 kiz_0987 <kp.0987 at gmail.com>

> I'm new to Mathematica and have a question regarding matrices. I was
> sure that this problem must have been answered in the past, but could
> not find a solution.
>
> I want to replace some elements in a matrix (based on value) with
> elements from another matrix at the same position. Eg:
> a = {{0, 1}, {1, 2}};
> b = {{1, 3}, {2, 5}};
>
> I want to replace the elements in "a" which are equal to 1 (say) with
> the same position elements in b to give:
> c = {{0, 3}, {2, 2}};
>
> How can I do this? I started with using Position and ReplacePart but
> could not figure out how to get it to work in this case (other cases
> are documented, such as replacing with a single value).
>
> Any help appreciated. Thanks.
>
>

```

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