Re: Replace elements in a matrix

• To: mathgroup at smc.vnet.net
• Subject: [mg116483] Re: Replace elements in a matrix
• From: Ray Koopman <koopman at sfu.ca>
• Date: Wed, 16 Feb 2011 06:45:23 -0500 (EST)
• References: <ijdo8r\$f7a\$1@smc.vnet.net>

```On Feb 15, 3:32 am, kiz_0987 <kp.0... at gmail.com> wrote:
> I'm new to Mathematica and have a question regarding matrices. I was
> sure that this problem must have been answered in the past, but could
> not find a solution.
>
> I want to replace some elements in a matrix (based on value) with
> elements from another matrix at the same position. Eg:
> a = {{0, 1}, {1, 2}};
> b = {{1, 3}, {2, 5}};
>
> I want to replace the elements in "a" which are equal to 1 (say) with
> the same position elements in b to give:
> c = {{0, 3}, {2, 2}};
>
> How can I do this? I started with using Position and ReplacePart but
> could not figure out how to get it to work in this case (other cases
> are documented, such as replacing with a single value).
>
> Any help appreciated. Thanks.

I'm surprised no one suggested this:

a = {{0, 1}, {1, 2}};
b = {{1, 3}, {2, 5}};
c = MapThread[If[#1 == 1, #2, #1] &, {a, b}, 2]

{{0, 3}, {2, 2}}

```

• Prev by Date: Re: Texture with transparency not working
• Next by Date: Re: Approximation
• Previous by thread: Re: Replace elements in a matrix
• Next by thread: How to do quickest