Re: making a parameter in an integrand real
- To: mathgroup at smc.vnet.net
- Subject: [mg116758] Re: making a parameter in an integrand real
- From: Bob Hanlon <hanlonr at cox.net>
- Date: Sat, 26 Feb 2011 06:08:01 -0500 (EST)
Integrate[1/(Cos[x] Sqrt[Cos[x]^2 - a2]), x] ArcTanh[(Sqrt[2]*Sqrt[-a2]*Sin[x])/Sqrt[1 - 2*a2 + Cos[2*x]]]/Sqrt[-a2] Assuming[a2 > 0, Simplify[Integrate[1/(Cos[x] Sqrt[Cos[x]^2 - a2]), x]]] ArcTan[(Sqrt[2]*Sin[x])/Sqrt[(1 - 2*a2 + Cos[2*x])/a2]]/Sqrt[a2] Bob Hanlon ---- alan <alansbarnett at verizon.net> wrote: ============= How do I get mathematica to consider a parameter in an integrand to be real. Example: In[1]:Integrate[1/(Cos[x] Sqrt[Cos[x]2 - a2]), x] ArcTanh[(Sqrt[2] Sqrt[-a2] Sin[x])/Sqrt[1 - 2 a2 + Cos[2 x]]]/Sqrt[- a2] But I want a2>0 (a real).