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Re: quadp

• To: mathgroup at smc.vnet.net
• Subject: [mg115227] Re: quadp
• From: Andrzej Kozlowski <akoz at mimuw.edu.pl>
• Date: Tue, 4 Jan 2011 18:49:15 -0500 (EST)
• References: <ifs30a$oor$1@smc.vnet.net> <4D21F917.2020209@cs.berkeley.edu> <48AEFA8B-880D-4B9A-B9CC-C1C7414D1384@mimuw.edu.pl> <A934FC78-8B93-45FB-A48D-D5BE2606760E@mimuw.edu.pl> <4D2254B8.8080703@eecs.berkeley.edu> <CE956DA2-464F-4CFB-B2BB-8E4AEBB83CF4@mimuw.edu.pl>

On 4 Jan 2011, at 07:27, Andrzej Kozlowski wrote:

>
> On 3 Jan 2011, at 23:59, Richard Fateman wrote:
>
>> On 1/3/2011 12:28 PM, Andrzej Kozlowski wrote:
>>>
>>> I forgot one obvious matter. A better way to solve this problem is:
>>>
>>> quadp[f_, x_] /; PolynomialQ[f, x]&&  Exponent[f, x] == 2 :=
>>> qq @@ CoefficientList[f, x]
>>>
>>> quadp[5 + 4*x + 3*x^2, x]
>>>
>>> qq(5,4,3)
>>>
>>> quadp[r*x^2 + s*x^2, x]
>>>
>>> qq(0,0,r+s)
>>
>> yours does not work for quadp[(x^3+x)/x, x], which I think is a quadratic.
>> my program agrees with me.
>>
>
> If you are going to include non-explcit polynomials than of course you need to use Simplify. Try your program on, for example,  (Sin[x]^2 + Cos[x]^2) x  or lots of other expressions of this kind. This is a "polynomial" as much as (x^3+x)/x is.
>
> Andrzej Kozlowski
>

Obviously I meant  (Sin[x]^2 + Cos[x]^2) x^2.

AK.