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Re: AstronomicalData. How can be taken into account when a planet is

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  • Subject: [mg115257] Re: AstronomicalData. How can be taken into account when a planet is
  • From: DrMajorBob <btreat1 at austin.rr.com>
  • Date: Wed, 5 Jan 2011 05:47:58 -0500 (EST)

Your plot is not a closed loop (like a figure eight), as one might expect  
an analemma to be.

Is that the issue that concerned you?

Bobby

On Tue, 04 Jan 2011 19:48:21 -0600, DrMajorBob <btreat1 at austin.rr.com>  
wrote:

> You can check whether distance to the sun is greater or less than  
> distance to the planet, but I think the answer is that your code already  
> takes it into account.
>
> Mathematica computes the 2-dimensional position of Venus in the sky; you  
> don't need distance - just altitude and azimuth.
>
> Bobby
>
> On Tue, 04 Jan 2011 17:49:27 -0600, Guillermo Sanchez  
> <guillermo.sanchez at hotmail.com> wrote:
>
>> Dear friend,
>> I have represented the venus analemma for 2 next years as follow
>> pos = $GeoLocation
>> zone = $TimeZone
>> analemmavenus = Table[{
>>     AstronomicalData["Venus", {"Azimuth", {2011, 1, i, 6}, pos},
>>      TimeZone -> zone],
>>     AstronomicalData["Venus", {"Altitude", {2011, 1, i, 6}, pos},
>>      TimeZone -> zone]}, {i, 1, 2*365.25, 10}];
>> Graphics[{Orange, Point[analemmavenus]}, Frame -> True,
>>  FrameLabel -> {"azimut", "altitud"}]
>>
>> Is it taken into account when the planet is behind the Sun?
>> It the answer is negative. How can be taken into account that a planet
>> is  behind the Sun?
>> HNY
>> Guillermo
>>
>
>


-- 
DrMajorBob at yahoo.com


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