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Re: fill in harberger triangle
*To*: mathgroup at smc.vnet.net
*Subject*: [mg115563] Re: fill in harberger triangle
*From*: "Sjoerd C. de Vries" <sjoerd.c.devries at gmail.com>
*Date*: Sat, 15 Jan 2011 04:42:37 -0500 (EST)
*References*: <igpbjo$fg9$1@smc.vnet.net>
I usually cheat by drawing the same graph twice, with slightly
different settings like below:
a = 10.2;
e = 1.4;
q[p_] = 10.2 p^1.4;
lowerBound = p /. Solve[q[p] == 100, p][[1]] // Quiet;
Show[
Plot[q[p], {p, 0, 30}, PlotRange -> {0, Automatic},
Epilog -> {Line[{{0, 100}, {30, 100}}],
Line[{{20, 0}, {20, 1200}}]}],
Plot[q[p], {p, lowerBound, 20}, Filling -> 100]
]
BTW I take it you meant to say: a horizontal line with Q (instead of
P) = 100 and a vertical line with P (instead of Q) = 20
Cheers -- Sjoerd
On Jan 14, 12:21 pm, r_poetic <radford.scha... at mms.gov> wrote:
> Hello,
> while the Filling option for Plot is great, how can I use it (or
> another feature of Mathematica 8) to fill in only the area between a
> curve and a vertical line and a horizontal line? For instance,
> between (1) the function Q= A * P ^ E, where A and E are given
> constants, (2) a horizontal line e.g. P = 100, and (3) a vertical
> line, e.g. Q = 20. The fill is only inside the triangle-like area.
> This would be the "harberger triangle" showing consumer surplus in
> economics.
>
> Thanks!
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