Re: fill in harberger triangle

*To*: mathgroup at smc.vnet.net*Subject*: [mg115563] Re: fill in harberger triangle*From*: "Sjoerd C. de Vries" <sjoerd.c.devries at gmail.com>*Date*: Sat, 15 Jan 2011 04:42:37 -0500 (EST)*References*: <igpbjo$fg9$1@smc.vnet.net>

I usually cheat by drawing the same graph twice, with slightly different settings like below: a = 10.2; e = 1.4; q[p_] = 10.2 p^1.4; lowerBound = p /. Solve[q[p] == 100, p][[1]] // Quiet; Show[ Plot[q[p], {p, 0, 30}, PlotRange -> {0, Automatic}, Epilog -> {Line[{{0, 100}, {30, 100}}], Line[{{20, 0}, {20, 1200}}]}], Plot[q[p], {p, lowerBound, 20}, Filling -> 100] ] BTW I take it you meant to say: a horizontal line with Q (instead of P) = 100 and a vertical line with P (instead of Q) = 20 Cheers -- Sjoerd On Jan 14, 12:21 pm, r_poetic <radford.scha... at mms.gov> wrote: > Hello, > while the Filling option for Plot is great, how can I use it (or > another feature of Mathematica 8) to fill in only the area between a > curve and a vertical line and a horizontal line? For instance, > between (1) the function Q= A * P ^ E, where A and E are given > constants, (2) a horizontal line e.g. P = 100, and (3) a vertical > line, e.g. Q = 20. The fill is only inside the triangle-like area. > This would be the "harberger triangle" showing consumer surplus in > economics. > > Thanks!