Re: Interpolation of a tabulated function

*To*: mathgroup at smc.vnet.net*Subject*: [mg115603] Re: Interpolation of a tabulated function*From*: DrMajorBob <btreat1 at austin.rr.com>*Date*: Sun, 16 Jan 2011 05:52:25 -0500 (EST)

That throws a warning, but this does not: x = RandomReal[{0, 10}, {20}];(*Generate random x*)data = Transpose[{x, x^2}] (*The function is now y=x^2*) intFunc = Interpolation[data]; Show[ListPlot[data], Quiet@Plot[intFunc[x], {x, 0, 10}]] or this: x = RandomReal[{0, 10}, {20}];(*Generate random x*)data = Transpose[{x, x^2}] (*The function is now y=x^2*) {min, max} = Through[{Min, Max}@data[[All, 1]]] intFunc = Interpolation[data]; Show[ListPlot[data], Plot[intFunc[x], {x, min, max}]] Bobby On Sat, 15 Jan 2011 03:44:30 -0600, Gabriel Landi <gtlandi at gmail.com> wrote: > Sorry if I misunderstood the problem but would it be something like the > following? > > x=RandomReal[{0,10},{20}]; (*Generate random x*) > > data=Transpose[{x,x^2}] (*The function is now y=x^2*) > > intFunc=Interpolation[data]; > > Show[ListPlot[data],Plot[intFunc[x],{x,0,10}]] > > It worked over here > Hope it helps, > > Gabriel > > On Fri, Jan 14, 2011 at 9:16 AM, girl17 <irexxy at gmail.com> wrote: > >> So, I have a list for tabulated function like that: >> {{x1,y1},{x2,y2},...,{xn,yn}}, where x(i+1)-xi are not equal for all i. >> I want to get an interpolated function for that array and to use this >> function in this way: intFucn[x], where x1<=x<=xn. >> I tried to use ListInterpolation[], but it works only for 1D lists, >> i.e. in >> case if x(i+1)-xi are equal for all i. >> Is there any solution for this problem? >> >> -- DrMajorBob at yahoo.com