Re: How to force numeric output

• To: mathgroup at smc.vnet.net
• Subject: [mg115658] Re: How to force numeric output
• From: Peter Pein <petsie at dordos.net>
• Date: Mon, 17 Jan 2011 05:41:59 -0500 (EST)
• References: <igrqb1\$qmq\$1@smc.vnet.net> <iguirf\$8tl\$1@smc.vnet.net>

```On 16.01.2011 11:55, KenR wrote:
> On Jan 15, 4:45 am, KenR<ramsey2... at msn.com>  wrote:
>> I am new to Mathematica and cant seem to get it to give a numeric
>>
>>   input    y = 5; x = floor[sqrt[y+1.0]]; x.
>>
>> instead of a numeric it gives "out floor[sqrt[6.0]]"
>>
>> what am I doing wrong?
>>
>> I have Mathematica 8.0
>>
>> Thankyou, Kenneth Ramsey
>
> I was looking at past posts and came upon a similar situation.  Thanks
> to those who e-mail me I am aware that the functions Floor and Sqrt
> must be capitalized.  It still apparently will not work because
> Mathematica does not know whether a positive or negative answer is
> desired.
>
> A similar situation was posted below where the sqrt of meter^2 etc was
> desired. A reader responded to write the code "Assuming[
> {Positive[Meter], Positive[Second]},
>    Refine[(Sqrt[Meter^2/Second^2] Second)/Meter^2]
>
> How would I invoke a similar solution to my case?
>
Sorry, this does not make sense to me.
You've got y=5 and z in z=Sqrt[y+1] is defined to be the positive
solution of x^2=6 (in this case). So there are no assumption needed.
Maybe I misunderstand your question :(

Do you want both values Floor[+/-Sqrt[6]]?
With[{y = 5},
x = Floor[z] /. Solve[z^2 == 1 + y, z]
]
will assign {-3,2} to x

Peter

```

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