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Evaluation of limit


If I give the command

In[1]:= Limit[Cosh[x]+Sinh[x]^2*Log[Tanh[x/2]],x->Infinity]

I get
                                 x          2
Out[1]= Limit[Cosh[x] + Log[Tanh[-]] Sinh[x] , x -> Infinity]
                                 2
 
instead of zero. This result can be verified numerically (of course, by 
using higher precision than the default).

Regards

C. S. Jog


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