Evaluation of limit
- To: mathgroup at smc.vnet.net
- Subject: [mg115692] Evaluation of limit
- From: "Dr. C. S. Jog" <jogc at mecheng.iisc.ernet.in>
- Date: Tue, 18 Jan 2011 05:52:15 -0500 (EST)
If I give the command
In[1]:= Limit[Cosh[x]+Sinh[x]^2*Log[Tanh[x/2]],x->Infinity]
I get
x 2
Out[1]= Limit[Cosh[x] + Log[Tanh[-]] Sinh[x] , x -> Infinity]
2
instead of zero. This result can be verified numerically (of course, by
using higher precision than the default).
Regards
C. S. Jog