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Evaluation of limit

  • To: mathgroup at
  • Subject: [mg115692] Evaluation of limit
  • From: "Dr. C. S. Jog" <jogc at>
  • Date: Tue, 18 Jan 2011 05:52:15 -0500 (EST)

If I give the command

In[1]:= Limit[Cosh[x]+Sinh[x]^2*Log[Tanh[x/2]],x->Infinity]

I get
                                 x          2
Out[1]= Limit[Cosh[x] + Log[Tanh[-]] Sinh[x] , x -> Infinity]
instead of zero. This result can be verified numerically (of course, by 
using higher precision than the default).


C. S. Jog

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