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Re: Suming InterpolatingFunction Objects

  • To: mathgroup at smc.vnet.net
  • Subject: [mg120240] Re: Suming InterpolatingFunction Objects
  • From: DrMajorBob <btreat1 at austin.rr.com>
  • Date: Thu, 14 Jul 2011 21:19:03 -0400 (EDT)
  • References: <201107140922.FAA15682@smc.vnet.net>
  • Reply-to: drmajorbob at yahoo.com

> sum = FunctionInterpolation[
>    Evaluate[Table[
>      D[Evaluate[x[t] + y[t] /. s], {{t}, k}], {k, 0, 2}]], {t, 0, 20},
>    InterpolationPoints -> 30]
> (* then you get away with less InterpolationPoints *)

I have two questions about that:

(1) The second Evaluate has no effect -- correct? -- since  
FunctionInterpolation holds ENTIRE arguments, not parts of them.

(2) Help gives an example something like this, but among the basic  
function forms at the top of the page, there are no templates involving a  
Table as the first argument. What is Help trying NOT to explain?

Bobby

On Thu, 14 Jul 2011 06:14:09 -0500, Oliver Ruebenkoenig  
<ruebenko at wolfram.com> wrote:

> On Thu, 14 Jul 2011, Gabriel Landi wrote:
>
>> Hello everyone.
>>
>> I encountered the following problem, which I am not sure is a bug or  
>> simply
>> a annoying detail.
>> I will use as an example a piece of code from the mathematica tutorials.
>>
>> Say I solve a system of ODEs
>>
>> s = NDSolve[{x'[t] == -y[t] - x[t]^2, y'[t] == 2 x[t] - y[t]^3,
>>   x[0] == y[0] == 1}, {x, y}, {t, 20}]
>>
>> My quantity of interest could be x[t] + y[t]. I can plot it:
>>
>> Plot[x[t] + y[t] /. s, {t, 0, 20}]
>>
>> But say I wish to store it as a single object.
>> So I do (this is the kinky part):
>>
>> sum = FunctionInterpolation[x[t] + y[t] /. s, {t, 0, 20}]
>>
>> Now, when I plot the result, it comes out completely different. It looks
>> like something changed with the interpolation order or something.
>>
>> Plot[sum[t], {t, 0, 20}]
>>
>> What do you guys think?
>>
>> Best regards,
>>
>> Gabriel
>>
>
> Gabriel,
>
> here are two alternatives:
>
> You could sample at more points via
>
> sum = FunctionInterpolation[Evaluate[x[t] + y[t] /. s], {t, 0, 20},
>    InterpolationPoints -> 100]
>
>
> additionally specifying the derivatives may be a good idea:
>
> sum = FunctionInterpolation[
>    Evaluate[Table[
>      D[Evaluate[x[t] + y[t] /. s], {{t}, k}], {k, 0, 2}]], {t, 0, 20},
>    InterpolationPoints -> 30]
> (* then you get away with less InterpolationPoints *)
>
> or do it manually as follows:
>
> The good thing here is that the NDSolve solutions are sampled at the same
> points.
>
> tutorial/NDSolvePackages#120436095
>
> s = NDSolve[{x'[t] == -y[t] - x[t]^2, y'[t] == 2 x[t] - y[t]^3,
>     x[0] == y[0] == 1}, {x, y}, {t, 20}]
>
> Needs["DifferentialEquations`InterpolatingFunctionAnatomy`"]
>
> domain = InterpolatingFunctionDomain[if1]
>
> {coords1} = InterpolatingFunctionCoordinates[if1];
> {coords2} = InterpolatingFunctionCoordinates[if2];
>
> Norm[coords1 - coords2, 1]
>
> vals1 = InterpolatingFunctionValuesOnGrid[if1];
> vals2 = InterpolatingFunctionValuesOnGrid[if2];
>
> if3 = Interpolation[Transpose[{coords1, vals1 + vals2}]]
>
> Plot[if3[x], {x, 0, 20}]
>
> Hope this helps.
>
> Oliver
>


-- 
DrMajorBob at yahoo.com


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