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Re: Overriding the definition of Plus so that it does exact arithmetic: Bug or Feature?

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  • Subject: [mg120257] Re: Overriding the definition of Plus so that it does exact arithmetic: Bug or Feature?
  • From: Dana DeLouis <dana01 at me.com>
  • Date: Fri, 15 Jul 2011 04:09:05 -0400 (EDT)

> This works as expected,  e.g.

> P[0.1, -1/10]  returns 1/180143985094819840

Not sure, but is this a good alternative?

p[v___]:=Total[Rationalize[List@v,0]]

p[0.1,-1/10]
0

p[a,1./3,1.1,2.3,5.6,2/3.]
10+a

= = = = = = = = = = 
HTH  : >) 
Dana DeLouis 
$Version 
8.0 for Mac OS X x86 (64-bit) (November 6, 2010) 


On Jul 14, 5:24 am, Richard Fateman <fate... at cs.berkeley.edu> wrote:
> Consider the definition of the new function P which is supposed to be
> exactly like Plus, except that converts all "Real" floats to exact
> rational numbers before adding them up.
> 
> P[a_Real,b__]:= Plus[Rationalize[SetAccuracy[a, Infinity]], b];
> SetAttributes[P, Attributes[Plus]]
> 
> P[c__]:= Plus[c]
> 
> This works as expected,  e.g.
> 
> P[0.1, -1/10]  returns 1/180143985094819840
> 
> which is the difference between the closest double-float to 0.1,
> and the exact number 1/10.
> 
> Given this, let's put EXACTLY the same definition on Plus
> 
> Unprotect[Plus];
> Plus[a_Real,b__]:= Plus[Rationalize[SetAccuracy[a, Infinity]], b];
> Protect[Plus];
> 
> 0.1-1/10  gives 0.   (wrong)
> 0.1+x gives 3602879701896397/36028797018963968 + x  (hm, right).
> 
> My guess is that any Rules inserted on Plus by the user are checked
> AFTER the built-in simplifications attached to Plus. I consider this a
> bug. Any workaround come to mind, if you consider this a feature :)
> 
> RJF



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