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Re: Compile and Total
Dear All,
I apologize for my mistakes. My only excuse is that I am using some drug
now, hopefully only for a few days, that is dangerous a.o. in
combination with driving, and, as I find now, also in combination with
Mathematica. I simply did not see that my 'better' code in my second
mail was incorrect in the first example. Neil found a way to overcome
it, by giving g head Function instead of Symbol. I have not observed
this before, but from this example it seems that
InlineExternalDefinitions does a check on the heads such that when an
external g is used as a function and does not have head Function, the
external definition will not be used.
In my first mail I used the With construct for substituting the
definitions into the expression to be compiled. But having done so, then
obviously (for me only now) there is no reason for using CompilationOptions:
<< CompiledFunctionTools`;
g = Total;
With[{g = g}, gC = Compile[{{x, _Real, 1}}, g[x]]];
CompilePrint[gC]
h = #/Total[#] &;
With[{h = h}, hC = Compile[{{x, _Real, 1}}, h[x]]];
CompilePrint[hC]
Fred
Op 15-7-2011 12:32, Neil Stewart schreef:
> Fred, DrMajorBob, Patrick---thank you very much for your replies. Continuing
> Fred's code:
>
> <<CompiledFunctionTools`;
>
> (* This does not compile *)
> g = Total;
> gC = Compile[{{x, _Real, 1}}, g[x],
> CompilationOptions -> {"InlineExternalDefinitions" -> True}];
> CompilePrint[gC]
>
> (* This does *)
> g = Total[#]&;
> gC = Compile[{{x, _Real, 1}}, g[x],
> CompilationOptions -> {"InlineExternalDefinitions" -> True}];
> CompilePrint[gC]
>
> I don't understand why, so I must be missing something fundamental about
> functions. Do you know the Mathematica keyword for the concept I'm missing?
>
> Thanks,
> Neil.
>
>
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