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Re: Question about function construction

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  • Subject: [mg119488] Re: Question about function construction
  • From: Leonid Shifrin <lshifr at>
  • Date: Mon, 6 Jun 2011 06:24:09 -0400 (EDT)

What you effectively coded is that for every unknown key, the full hash
table is re-created.  You Map the assignment (Set) on a list of keys, and
get a list of assigned values.  The second time, you already have a specific
definition for that key, so that one fires, and you get a single value. Here
is what you should have done, in your approach:

ConstructHashtable[] :=
 Module[{pairs = {{"key1", "value1"}, {"key2", "value2"}, {"key3",
      "value3"}, {"key4", "value4"}}},
  (Hashtable[#[[1]]] = #[[2]]) & /@ pairs;]

although it would seem more natural to me to make the original keys and
values arguments for your constructor, as well as the hash table name.


On Sun, Jun 5, 2011 at 4:04 AM, ZiYuan Lin <ziyuang at> wrote:

> Hi, there.
>  I want to construct a function serving as a hash table. This is how I make
> it:
>  ConstructHashtable[] :=
>   Module[{pairs = {{"key1", "value1"}, {"key2", "value2"}, {"key3",
>        "value3"}, {"key4", "value4"}}}, Clear[Hashtable];
>    Hashtable[key_?StringQ] := (Hashtable[#[[1]]] = #[[2]]) & /@ pairs;]
> And then I run the code above together with a test:
>  ConstructHashtable[]; Hashtable["key1"]
> Yet it returns all values:
>  {"value1", "value2", "value3", "value4"}
> But if I run it again:
>  Hashtable["key1"]
> It will get normal:
>  "value1"
> What is the reason for this? Thank you~

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