Mathematica 9 is now available
Services & Resources / Wolfram Forums / MathGroup Archive
-----

MathGroup Archive 2011

[Date Index] [Thread Index] [Author Index]

Search the Archive

Re: querries

  • To: mathgroup at smc.vnet.net
  • Subject: [mg119574] Re: querries
  • From: "Kevin J. McCann" <Kevin.McCann at umbc.edu>
  • Date: Fri, 10 Jun 2011 06:40:15 -0400 (EDT)
  • References: <isq4o1$63f$1@smc.vnet.net>

It is probably because powers, x^y are multivalued. You can use 
expr//PowerExpand to short circuit these concerns. Be aware, however 
that the following does not give an answer

Sqrt[b^2]==b

but

Sqrt[b^2]==b//PowerExpand

Gives True, which means that the concerns about plus/minus are forgotten.

Kevin


On 6/9/2011 5:45 AM, Savits, Thomas H wrote:
> 1)       Why does Mathematica not give the value 0 to the expression
> (mu*lambda)^(b) - (mu^b)*(lambda^b)? It seems to treat the expression (mu*lambda) as a new variable. I used the greek letters from the palette in the actual expression.
>
> 2)       Many times I cannot get Mathematica to simplify expressions involving the exponential functions, e.g., it won't combine the arguments of the Exp functions. Is there a way to force this?
>
> Thanks,
> Tom Savits
> Statistics Department
> University of Pittsburgh


  • Prev by Date: How to make the same two expressions
  • Next by Date: Re: querries
  • Previous by thread: Re: querries
  • Next by thread: Re: querries