MathGroup Archive 2011

[Date Index] [Thread Index] [Author Index]

Search the Archive

Re: How to transform a functional expression into a general expression


I see NO reason to call one of those equations more "general" than the  
other, but this may do what you want (sometimes):

y == 3/2 x + 1 // Simplify
Subtract @@ % == 0

2 + 3 x == 2 y

2 + 3 x - 2 y == 0

Bobby

On Tue, 21 Jun 2011 07:35:58 -0500, sigismond kmiecik  
<sigismond.kmiecik at wanadoo.fr> wrote:

> Hello  to all
>
> I will take a simple example.
>
> How can you easily transform using Mathematica  the following functional
> expression
>
> y = 3/2 x + 1
>
> into its general equivalent:
>
> 3 x - 2 y  + 2 = 0
>
>
> This general form exists  because
>
> y == 3/2 x + 1 // FullSimplify
>
> returns True.
>
> Is the answer given valid whatever the complexity  of the initial
> equality expression  known to be true (with up to three unknown  
> variables).
>
> Thanks
>
> Sigismond Kmiecik
>


-- 
DrMajorBob at yahoo.com


  • Prev by Date: Re: pairing values from a list
  • Next by Date: Re: pairing values from a list
  • Previous by thread: How to transform a functional expression into a general expression
  • Next by thread: pairing values from a list