Re: Joining points of ListPlot

• To: mathgroup at smc.vnet.net
• Subject: [mg117283] Re: Joining points of ListPlot
• From: Antonio Mezzacapo <ant.mezzacapo at gmail.com>
• Date: Mon, 14 Mar 2011 05:57:45 -0500 (EST)

```Tha problem is that all points are on the same array, and I don't know the
functional form they have, so i can't separate the two arrays like you did
It's like having Sin and Cos points on the same array, but they are not Sin
and Cos, and I don't know their analytic form!

AM

2011/3/13 Michael Stern <nycstern at gmail.com>

> Can you provide an example of your data? Sorting by the independent
> variable should give you the results you want, as in my third example.
>
> MS
>
> Sent from a mobile device.
>
> On Mar 13, 2011, at 8:24 AM, Antonio Mezzacapo <ant.mezzacapo at gmail.com>
> wrote:
>
>
> I don't have any functional form of this points. I have only this array of
> points. Points on this array should be distributed *like* two crossing
> functions as Sin[x] and Cos[x], but I don't know the functional form of
> these functions.
>
> All that I have is an array of points!
> Because of the fact that these points distribute on the x-y cartesian plane
> like two crossing functions, I cannot use "joined->true" because it gives me
> strange results.
>
> Thank you
> Antonio
>
> 2011/3/13 Michael Stern < <nycstern at gmail.com>nycstern at gmail.com>
>
>> Antonio,
>>
>> Some points of your question are unclear, but perhaps this will cover all
>> relevant cases.
>>
>> 1. If you have functions, the simplest way is:
>>
>> Plot[{Sin[x], Cos[x]}, {x, 0, 2*Pi}]
>>
>> 2. You refer to "joined points," however, which suggests that you may be
>> dealing with lists of points rather than functions. If so, you can do the
>> same thing as follows:
>>
>> (* creating the two lists *)
>> s1 = Table[Sin[x], {x, 0, 2*Pi, .1}];
>> c1 = Table[Cos[x], {x, 0, 2*Pi, .1}];
>>
>> (* plot *)
>> ListPlot[{s1, c1}, Joined -> True]
>>
>>
>> 3. You refer to the points not being ordered, from which I take that one
>> or both of the lists of plots has cartesian coordinates, not ordered by the
>> independent variable. In this case, you can use Sort or SortBy to put them
>> in order.
>>
>> (* creating two cartesian lists, neither of which is 'ordered' by the
>> definition above *)
>> s2 = RotateLeft[Table[{x, Sin[x]}, {x, 0, 2*Pi, .1}]];
>> c2 = RotateRight[Table[{x, Cos[x]}, {x, 0, 2*Pi, .1}]];
>>
>> (* plot by sorted versions of these unordered lists *)
>> ListPlot[{SortBy[s2, First], SortBy[c2, First]}, Joined -> True]
>>
>>
>> Does that help?
>>
>> Michael
>>
>>
>> On Mar 13, 2011, at 6:25 AM, Antonio Mezzacapo wrote:
>>
>> > Hi,
>> > here's my problem:
>> >
>> > I have an array of data depicting two crossing functions (let's say like
>> > Sin[x] and Cos[x]). How can I arrange them and make a joined points
>> plot,
>> > that joins only points belonging to the same function?
>> > I remember you that the points of the two crossing functions are on the
>> same
>> > array and they are non-ordered.
>> >
>> > Thank you
>> >
>> > Antonio Mezzacapo
>> >
>>
>>
>

```

• Prev by Date: Re: How to interactively re-scale graphics with mouse?
• Next by Date: Re: Joining points of ListPlot
• Previous by thread: Re: Joining points of ListPlot
• Next by thread: Re: Joining points of ListPlot