Re: Series[log[x], {x, 0, 3}]
- To: mathgroup at smc.vnet.net
- Subject: [mg119131] Re: Series[log[x], {x, 0, 3}]
- From: Bob Hanlon <hanlonr at cox.net>
- Date: Sun, 22 May 2011 06:57:52 -0400 (EDT)
It assumes that log is a user defined function. It doesn't know that you mean Log
Series[Log[x], {x, 0, 3}] // Normal
Log[x]
Series[Log[1 + x], {x, 0, 3}] // Normal
x - x^2/2 + x^3/3
Bob Hanlon
---- Hongyi Zhao <hszhao.cn at gmail.com> wrote:
=============
Hi all,
I do the following computation within Mathematica:
Series[log[x], {x, 0, 3}]
Then I get:
log[0]+(log^\[Prime])[0] x+1/2 (log^\[Prime]\[Prime])[0] x^2+1/6 (log^(3))
[0] x^3+O[x]^4
Any hints on this result? The log[0] is illegal in my mind.
Regards.
--
.: Hongyi Zhao [ hongyi.zhao AT gmail.com ] Free as in Freedom :.