Re: Series[log[x], {x, 0, 3}]
- To: mathgroup at smc.vnet.net
- Subject: [mg119103] Re: Series[log[x], {x, 0, 3}]
- From: DrMajorBob <btreat1 at austin.rr.com>
- Date: Sun, 22 May 2011 06:52:46 -0400 (EDT)
The function is called Log. (ALL Mathematica built-ins start with capital letters.) Log has a singularity at 0, so you'd have to expand around some other point, such as 1: Series[Log@x, {x, 1, 3}] (x-1)-1/2 (x-1)^2+1/3 (x-1)^3+O[x-1]^4 Bobby On Sat, 21 May 2011 05:44:59 -0500, Hongyi Zhao <hszhao.cn at gmail.com> wrote: > Hi all, > > I do the following computation within Mathematica: > > Series[log[x], {x, 0, 3}] > > Then I get: > > log[0]+(log^\[Prime])[0] x+1/2 (log^\[Prime]\[Prime])[0] x^2+1/6 > (log^(3)) > [0] x^3+O[x]^4 > > Any hints on this result? The log[0] is illegal in my mind. > > Regards. > -- > .: Hongyi Zhao [ hongyi.zhao AT gmail.com ] Free as in Freedom :. > -- DrMajorBob at yahoo.com