Re: get a, b from numbers in the form a+b Pi
- To: mathgroup at smc.vnet.net
- Subject: [mg119141] Re: get a, b from numbers in the form a+b Pi
- From: Murray Eisenberg <murray at math.umass.edu>
- Date: Mon, 23 May 2011 06:23:30 -0400 (EDT)
Here's another way that also handles the situation where a=0, but not
the situation where b = 0:
newnums = newnums = Join[{1, 2 Pi}, nums];
CoefficientList[#, Pi] & /@ Expand[newnums]
The "sneaky" part there is to realize that, since Pi is just a symbol,
it may be considered the variable in a polynomial!
On 5/22/2011 6:57 AM, 1.156 wrote:
> I have lists of numbers (Mathematica output) all numerically in the
> form a + b*Pi and I'm trying to extract the values of a and b for
> further work.
>
> Here's an example of the best I've been able to do so far:
>
> nums={1/2 (-2+\[Pi]),-2+(3 \[Pi])/4,-(11/3)+(5 \[Pi])/4,5/48 (-64+21
> \[Pi]),-(61/5)+(63 \[Pi])/16,-(338/15)+(231 \[Pi])/32};
> {FullForm[#][[1,1]],FullForm[#][[1,2]]/\[Pi]}&/@nums
>
> When I run this line of code 4 of the six input numbers give me the
> {a,b} I'm looking for but the first and fourth entries fail because the
> form isn't right. Possibly I could patch this scheme to look for a small
> finite set of possibilities of input number form but I suspect I may a
> long way from attacking this problem correctly.
>
> Can someone offer some other ideas on how to pull this off? Many thanks
> for looking at this. Rob
--
Murray Eisenberg murray at math.umass.edu
Mathematics & Statistics Dept.
Lederle Graduate Research Tower phone 413 549-1020 (H)
University of Massachusetts 413 545-2859 (W)
710 North Pleasant Street fax 413 545-1801
Amherst, MA 01003-9305