Re: Simple question about inverse of a function

• To: mathgroup at smc.vnet.net
• Subject: [mg122606] Re: Simple question about inverse of a function
• From: "E. Martín-Serrano" <eMartinSerrano at telefonica.net>
• Date: Thu, 3 Nov 2011 03:45:20 -0500 (EST)
• Delivered-to: l-mathgroup@mail-archive0.wolfram.com
• References: <201111010501.AAA14719@smc.vnet.net> <201111021122.GAA03555@smc.vnet.net>

```Both, David's and Bobby's (without beep) solutions work perfectly for me
too.

The David's plot looks pretty illustrative.

\$Version:   "8.0.1.0  for Microsoft Windows (64-bit) (February 23, 2011)"

-----Mensaje original-----
De: DrMajorBob [mailto:btreat1 at austin.rr.com]
Enviado el: mi=E9rcoles, 02 de noviembre de 2011 12:22
Para: mathgroup at smc.vnet.net
Asunto: Re: Simple question about inverse of a function

It works perfectly here (with an error beep you can ignore), and this does
the same... without the beep:

Clear[f, g]
f[theta_][t_] := (1 - t)^theta
g[theta_] = Quiet@InverseFunction[f[theta]]

1 - #1^(1/theta) &

\$Version

"8.0 for Mac OS X x86 (64-bit) (October 5, 2011)"

Bobby

On Tue, 01 Nov 2011 00:01:55 -0500, Mikael <mikaen.anderson.1969 at gmail.com>
wrote:

> Thanks David for your reply but unfortunately the solution does not
> work for me. I am running Mathematica 8 under Windows 7 and the last
> expression below does not result in any solution for me (I waited
> several minutes). This is a copy of my notebook which is exactly what
> you suggested:
>
> Clear[f,g]
> conditions=0<=t<=1&&1<=theta<=Infinity;
> f[theta_][t_]:=(1-t)^theta
> g[theta_]=Assuming[conditions,InverseFunction[f[theta]]]
>

--
DrMajorBob at yahoo.com

```

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