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Re: Graphics << Implicit vs ContourPlot
*To*: mathgroup at smc.vnet.net
*Subject*: [mg122754] Re: Graphics << Implicit vs ContourPlot
*From*: Heike Gramberg <heike.gramberg at gmail.com>
*Date*: Thu, 10 Nov 2011 06:49:07 -0500 (EST)
*Delivered-to*: l-mathgroup@mail-archive0.wolfram.com
*References*: <201111091124.GAA11084@smc.vnet.net>
Setting Axes -> True, Frame -> False in your ContourPlot will create a
plot with axes instead of a frame.
To plot the rotated ellipse it's probably easier to use Circle and
Rotate instead of ContourPlot. For example, this will plot an ellipse
with semi-axes 2 and 1 rotated over 45 degrees.
With[{ellipse = Circle[{0, 0}, {2, 1}], angle = 45 Degree},
Graphics[{ellipse,
{Red, Rotate[{ellipse, Line[{{-3, 0}, {3, 0}}], Line[{{0, -3}, {0,
3}}]}, angle]}},
Axes -> True, PlotRange -> {{-2.1, 2.1}, {-2.1, 2.1}}]]
Heike
On 9 Nov 2011, at 12:24, John Accardi wrote:
> Goal: Show students a plot of both an ellipse with x axis as ellipse's
> transverse axis
> and the same ellipse in an x'y' coordinate plane that is rotated some angle
> with respect the the original xy coordinate plane. (All in one plot)
>
> I used:
>
> << Graphics`ImplicitPlot`; ImplicitPlot[{7 x^2 - 6 Sqrt[3] x y +
> 13 y^2 - 16 == 0, ((x^2)/2^2) + ((y^2)/2^2) == 1, y == x,
> y == -x}, {x, -3, 3}, AspectRatio -> 1.25]
>
> which works well but I had to hard fix the axis of rotation at 45 degrees
> and plot it (y == x and y == -x). I also get an obsolete warning and
> the suggestion to use the new ContourPlot for this in the future:
>
> General::obspkg: "\!\(\"Graphics`ImplicitPlot`\"\) is now obsolete.
> The legacy version being loaded may conflict with current Mathematica
> functionality. See the Compatibility Guide for updating information."
>
> So I try to accomplish the same graph with ContourPlot:
>
> ContourPlot[{7 x^2 - 6 Sqrt[3] x y + 13 y^2 - 16 ==
> 0, ((x^2)/2^2) + ((y^2)/2^2) == 1, y == x, y == -x, y == 0,
> x == 0}, {x, -3, 3}, {y, -3, 3}, AspectRatio -> 1.25]
>
> which gets me close but I have lost traditional plotting of the xy axes
> (no tick marks). Instead I get ContourPlots boxed style coordinate system.
>
> Question: How can I get my old style axes back in the context of
> ContourPlot?
>
> Thank you for any insights.
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