Re: Loop problem

• To: mathgroup at smc.vnet.net
• Subject: [mg123073] Re: Loop problem
• From: Bob Hanlon <hanlonr357 at gmail.com>
• Date: Tue, 22 Nov 2011 05:37:01 -0500 (EST)
• Delivered-to: l-mathgroup@mail-archive0.wolfram.com
• References: <201111210927.EAA14761@smc.vnet.net>

```For i!=j!=k!=l, I assume that you mean that there must be four
distinct elements and that for this and the other cases that you must
mean 0 <= i,j,k,l <= 3

Select[Tuples[Range[0, 3], 4], Length[Union[#]] == 4 &]

{{0, 1, 2, 3}, {0, 1, 3, 2}, {0, 2, 1, 3}, {0, 2, 3, 1}, {0, 3, 1, 2}, {0, 3,
2, 1}, {1, 0, 2, 3}, {1, 0, 3, 2}, {1, 2, 0, 3}, {1, 2, 3, 0}, {1, 3, 0,
2}, {1, 3, 2, 0}, {2, 0, 1, 3}, {2, 0, 3, 1}, {2, 1, 0, 3}, {2, 1, 3,
0}, {2, 3, 0, 1}, {2, 3, 1, 0}, {3, 0, 1, 2}, {3, 0, 2, 1}, {3, 1, 0,
2}, {3, 1, 2, 0}, {3, 2, 0, 1}, {3, 2, 1, 0}}

For  i!=j=k!=l, I assume that you want three distinct elements with
positions 2 and 3 equal

Select[Tuples[Range[0, 3], 4], #[[2]] == #[[3]] && Length[Union[#]] == 3 &]

{{0, 1, 1, 2}, {0, 1, 1, 3}, {0, 2, 2, 1}, {0, 2, 2, 3}, {0, 3, 3, 1}, {0, 3,
3, 2}, {1, 0, 0, 2}, {1, 0, 0, 3}, {1, 2, 2, 0}, {1, 2, 2, 3}, {1, 3, 3,
0}, {1, 3, 3, 2}, {2, 0, 0, 1}, {2, 0, 0, 3}, {2, 1, 1, 0}, {2, 1, 1,
3}, {2, 3, 3, 0}, {2, 3, 3, 1}, {3, 0, 0, 1}, {3, 0, 0, 2}, {3, 1, 1,
0}, {3, 1, 1, 2}, {3, 2, 2, 0}, {3, 2, 2, 1}}

For  i!=j!=k=l, I assume that you want three distinct elements with
positions 3 and 4 equal

Select[Tuples[Range[0, 3], 4], #[[3]] == #[[4]] && Length[Union[#]] == 3 &]

{{0, 1, 2, 2}, {0, 1, 3, 3}, {0, 2, 1, 1}, {0, 2, 3, 3}, {0, 3, 1, 1}, {0, 3,
2, 2}, {1, 0, 2, 2}, {1, 0, 3, 3}, {1, 2, 0, 0}, {1, 2, 3, 3}, {1, 3, 0,
0}, {1, 3, 2, 2}, {2, 0, 1, 1}, {2, 0, 3, 3}, {2, 1, 0, 0}, {2, 1, 3,
3}, {2, 3, 0, 0}, {2, 3, 1, 1}, {3, 0, 1, 1}, {3, 0, 2, 2}, {3, 1, 0,
0}, {3, 1, 2, 2}, {3, 2, 0, 0}, {3, 2, 1, 1}}

For i!=k!=j=l , I assume that you want three distinct elements with
positions 2 and 4 equal

Select[Tuples[Range[0, 3], 4], #[[2]] == #[[4]] && Length[Union[#]] == 3 &]

{{0, 1, 2, 1}, {0, 1, 3, 1}, {0, 2, 1, 2}, {0, 2, 3, 2}, {0, 3, 1, 3}, {0, 3,
2, 3}, {1, 0, 2, 0}, {1, 0, 3, 0}, {1, 2, 0, 2}, {1, 2, 3, 2}, {1, 3, 0,
3}, {1, 3, 2, 3}, {2, 0, 1, 0}, {2, 0, 3, 0}, {2, 1, 0, 1}, {2, 1, 3,
1}, {2, 3, 0, 3}, {2, 3, 1, 3}, {3, 0, 1, 0}, {3, 0, 2, 0}, {3, 1, 0,
1}, {3, 1, 2, 1}, {3, 2, 0, 2}, {3, 2, 1, 2}}

Bob Hanlon

On Mon, Nov 21, 2011 at 4:27 AM, P Shar <puya.sharif at live.com> wrote:
> Hey guys, i need a loop (that does the following) and can't figure out what to do..
>
> I need a set of lists {i,j,k,l} i=E2=89 j=E2=89 k=E2=89 l, i=E2=89 j=k=E2=89 l, i=E2=89 j=E2=89 k=l, i=E2=89 k=E2=89 j=l where 0 < i,j,k,l < 3.
>
> So basically all the cases where the first condition holds and all the cases there the second holds etc..
>
> Easiest would be to get the output as a matrix with the {i,j,k,l}'s as rows.
>
> Any ideas (or at least where to start)?
>
> Cheers
>

```

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