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Re: count zeros in a number


On 10/3/2011 10:34 PM, Stefan Salanski wrote:

>
> All these solutions are very interesting, and they all work, but I
> believe the simplest solution is actually a built in function,
> specifically: IntegerExponent[].
> IntegerExponent[n,b] returns the highest power of b which divides n,
> which for b=10, is the number of trailing zeroes of n.
>
why yes, all you need is one esoteric function.
Proof that it is esoteric?  All the previous posters (me too) were 
unaware of it. And presumably all the people who read the question and
did not post anything ...


The first example in the documentation illustrates exactly this usage.

RJF




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