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Re: List plot with random size for each point

  • To: mathgroup at smc.vnet.net
  • Subject: [mg122457] Re: List plot with random size for each point
  • From: Heike Gramberg <heike.gramberg at gmail.com>
  • Date: Sat, 29 Oct 2011 07:10:07 -0400 (EDT)
  • Delivered-to: l-mathgroup@mail-archive0.wolfram.com
  • References: <201110280936.FAA20855@smc.vnet.net>

I'm not entirely sure what you mean with the last line. Do you want the 
PointSize of the point at position position[[n]] to be equal to 
particle[[n,2]]?
If so, you could do something like

Graphics[MapThread[{AbsolutePointSize[#1/3], Point[#2]} &, 
{particle[[All,2]], position}], Axes -> True]

By the way, a more typical way in Mathematica to generate the lists 
particle and position as in your example is to do something like

particle = Table[{i, RandomInteger[{15, 25}], RandomInteger[{0, 200}], 
RandomInteger[{0, 200}]}, {i, 200}];
position = particle[[All, {3, 4}]];

Heike.


On 28 Oct 2011, at 11:36, Rudresh wrote:

> I want to plot an array of numbers on a 2d plot, however each point 
has a random number associated with it which should be its size on the 
plot. Can this be done in mathematica and if so how. My code as of now 
is:
>
> =========================
>
> particle = Array[f, {200, 4}];
> position = Array[g, {200, 2}];
> n = 1;
> While  [n < 201,
>  	particle[[n, 1]] = n;
>  	particle[[n, 2]] = RandomInteger[{15, 25}];
>  	particle[[n, 3]] = RandomInteger[{0, 200}];
>  	particle[[n, 4]] = RandomInteger[{0, 200}];
>  
>  position[[n, 1]] = particle[[n, 3]];
>  position[[n, 2]] = particle[[n, 4]];
>  n++
>  ];
>
> ListPlot[position, PlotStyle -> PointSize[0.01],
> PlotRange -> {{0, 200}, {0, 200}}]
>
> =========================
>
> I want particle[[n,2]] to be the size of position[[n,1],[n,2]]
>




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