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Re: Calculus and InterpolatingFunction
*To*: mathgroup at smc.vnet.net
*Subject*: [mg121610] Re: Calculus and InterpolatingFunction
*From*: "Oleksandr Rasputinov" <oleksandr_rasputinov at hmamail.com>
*Date*: Thu, 22 Sep 2011 07:25:24 -0400 (EDT)
*Delivered-to*: l-mathgroup@mail-archive0.wolfram.com
*References*: <j5cb71$cvl$1@smc.vnet.net>
On Wed, 21 Sep 2011 10:36:33 +0100, Just A Stranger
<forpeopleidontknow at gmail.com> wrote:
> I'm trying to get a definite integral for an InterpolatingFunction. It
> works
> if it is the function by itself, but not for some reason arithmetically
> combining the InterpolatingFunction with another function makes it not
> return a value. e.g.
>
>
> In[1]:=
> data = RandomReal[#]*2 & /@ Range[1, 10];
> f = Interpolation[data];
>
>> Integrate[f[x], {x, 1, 10}]
> Out[1]:=40.098
>
> So far so good. But just a little bit of arithmetic in the integral and
> it
> doesn't work anymore:
> In[2]:=
> Integrate[f[x]+1, {x, 1, 10}]
> Out[2]:=
> Integrate[Plus[1, InterpolatingFunction[][x]], List[x, 1, 10]]
>
> (That last answer was actually the output with //FullForm applied)
> Why won't it give me a numerical evaluation? Is there anyway to make a
> continuous function from data that will seemlessly work with Integrate?
> I'm
> thinking of constructing a piecwise function using Fit, Piecwise, and a
> Table for the arguments to Piecewise. But I would think Interpolation
> might
> have worked and been easier. I want to figure out if I am I doing
> something
> wrong with Interpolation before I start trying to tackle a slightly more
> complicated piecewise defined function ?
This is slightly puzzling, though more in respect of why the first example
worked than why the second one didn't. If it's numerical integration you
wish to perform, NIntegrate is surely preferable to Integrate, and works
for both cases given above:
In[3] := NIntegrate[f[x], {x, 1, 10}]
Out[3] = 32.2367
In[4] := NIntegrate[f[x] + 1, {x, 1, 10}]
Out[4] = 41.2367
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