MathGroup Archive 2011

[Date Index] [Thread Index] [Author Index]

Search the Archive

Re: Integration error? Integrate[1/(x^3-1)]?


No, it's not an error. The two versions only differ by a constant, because Log[-1] = I Pi.  So for indefinite integrals it's fine.




  • Prev by Date: Re: A fast way to compare two vectors
  • Next by Date: Re: plotting equations
  • Previous by thread: Re: Integration error? Integrate[1/(x^3-1)]?
  • Next by thread: Re: Integration error? Integrate[1/(x^3-1)]?