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Re: simplify Arg[E^(I x)]?


FullSimplify[Arg[E^((x) I)], x > -Pi && x <= Pi]

This seems to do what I wanted.  Thanks!

On Sun, Apr 1, 2012 at 1:25 AM, Anthony Hodsdon <ajhodsd at hotmail.com> wrote:

> The following seems to work:
>
> In[24]:= FullSimplify[Arg[E^((2 Pi n + x) I)],  x > -Pi && x <= Pi &&
> Element[n, Integers]]
> Out[24]= x
>
> Does that help?
>
> --Anthony
>
> -----Original Message-----
> From: Neal Becker [mailto:ndbecker2 at gmail.com]
> Sent: Saturday, March 31, 2012 1:42 AM
> To: mathgroup at smc.vnet.net
> Subject: simplify Arg[E^(I x)]?
>
> Why doesn't this simplify?
>
> Fullsimplify[Arg[E^(I x)], x \[Element] Reals]
>
> I expect to get 'x'.
>
> Is there some way I can get this to simplify?
>
>
>




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