Re: recursively solve equation and save the values only
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- Subject: [mg125801] Re: recursively solve equation and save the values only
- From: nanobio9 <kuokan.liang at gmail.com>
- Date: Tue, 3 Apr 2012 04:47:15 -0400 (EDT)
- Delivered-to: l-mathgroup@mail-archive0.wolfram.com
- References: <jlbo31$47o$1@smc.vnet.net>
Hi,
My solution to your example would be:
solstab = (T/.#&)/@(sols/.{Equal->Rule})
Best regards,
Kuo Kan Liang
> I am new to Mathematica. I am trying to recursively solve equation and
> saving the values into Table. Since I need the real solutions only so
> I use Reduce.
>
> The following is my code:
>
> f = 5.68672 T + 6.46776 T^3
>
> t = Table[i, {i, 0.2, 3, 0.2}]
>
> sols = Table[Reduce[f == t[[i]], T, Reals], {i, Length[t]}] {T ==
> 0.0351204, T == 0.06995, T == 0.104221, T == 0.137708, T == 0.170237,
> T == 0.201687, T == 0.231988, T == 0.26111, T == 0.289058, T ==
> 0.315857, T == 0.34155, T == 0.366188, T == 0.389828, T == 0.412529, T
> == 0.434347}
>
> The solution is OK as I compared it to other software as well. The
> only thing that matters me is how to remove the T== , i.e. I just need
> the solution and then to copy this into another table, say sols2 that
> contains
>
> sols2 = {0.0351204, 0.06995, 0.104221, T == 0.137708,.., 0.434347}
>
> I tried the following: sols2 = T/.sols but produce the following
> error:
>
> sols2 = ReplaceAll::reps: ... is neither a list of replacement rules
> nor a valid dispatch table, and so cannot be used for replacing. >>
>
> Does anyone know how to remove the T==?
>
> Thank you,
>
> Wayan