FindFit and squared residuals
- To: mathgroup at smc.vnet.net
- Subject: [mg126214] FindFit and squared residuals
- From: leigh pascoe <leigh at evry.inserm.fr>
- Date: Wed, 25 Apr 2012 00:36:14 -0400 (EDT)
- Delivered-to: l-mathgroup@mail-archive0.wolfram.com
Is there a command to get the sum of the squared residuals after using FindFit? Here is an example that fits a function and then plots the data and the fitted function inc1[x_, M_, \[Tau]_, \[Phi]_] := M/\[Tau] \[Phi]^M E^(-(x/\[Tau])) (1 - E^(-(x/\[Tau])))^(M - 1) franceMaleCDdata19882005 = {{2.5, 0}, {7.5, .000008}, {12.5, .00004}, {17.5, .00012}, {22.5, \ .000142}, {27.5, .00012}, {32.5, .000084}, {37.5, 0.000060}, {42.5, .000050}, {47.5, .000046}, {52.5, .000039}, \ {57.5, 0.000043}, {62.5, .000022}, {67.5, .000026}, {72.5, .000016}, \ {77.5, 0.000019}, {82.5, .000015}, {87.5, .000017}}; franceMaleCDdata19882005plot = ListPlot[franceMaleCDdata19882005, PlotStyle -> {Red, Dashed, Thick}, PlotRange -> All, Joined -> True]; franceMaleCDdata19882005fit = FindFit[franceMaleCDdata19882005, inc1[x, M, \[Tau], \[Phi]], {{M, 10}, {\[Tau], 5}, {\[Phi], .6}}, x] Show[Plot[ inc1[x, M, \[Tau], \[Phi]] /. franceMaleCDdata19882005fit, {x, 0, 85}, PlotRange -> All], franceMaleCDdata19882005plot] What is the minimised value of the squared residuals in this case? I would like to compare the fit with the more complex function shown below (the fit is obviously better, but with more parameters used}. inc4[x_, N1_, N2_, \[Tau]1_, \[Tau]2_, \[Phi]_] := ( E^(-(x/\[Tau]1)) (1 - E^(-(x/\[Tau]1)))^(-1 + N1) (1 - E^(-(x/\[Tau]2)))^N2 N1 \[Phi]^(N1 + N2))/\[Tau]1 + ( E^(-(x/\[Tau]2)) (1 - E^(-(x/\[Tau]1)))^ N1 (1 - E^(-(x/\[Tau]2)))^(-1 + N2) N2 \[Phi]^(N1 + N2))/\[Tau]2 franceMaleCDdata19882005fit = FindFit[franceMaleCDdata19882005, inc4[x, N1, N2, \[Tau]1, \[Tau]2, \[Phi]], {{N1, 8}, {N2, 2}, {\[Tau]1, 7}, {\[Tau]2, 23}, {\[Phi], .6}}, x] Show[Plot[ inc4[x, N1, N2, \[Tau]1, \[Tau]2, \[Phi]] /. franceMaleCDdata19882005fit, {x, 0, 85}, PlotRange -> All], franceMaleCDdata19882005plot] Thanks for any help. Leigh
- Follow-Ups:
- Re: FindFit and squared residuals
- From: Darren Glosemeyer <darreng@wolfram.com>
- Re: FindFit and squared residuals