Re: Find Position of many elements in a large list.

• To: mathgroup at smc.vnet.net
• Subject: [mg127681] Re: Find Position of many elements in a large list.
• From: Peter Pein <petsie at dordos.net>
• Date: Wed, 15 Aug 2012 03:31:05 -0400 (EDT)
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```Am 14.08.2012 11:05, schrieb benp84 at gmail.com:
> I have a sorted, 1-dimensional list X of 1,000,000 integers, and a sorted, 1-dimensional list Y of 10,000 integers.  Most, but not all, of the elements of Y are also elements of X.  I'd like to know the positions of the elements in X that are also in Y.  What's the fastest way to compute this?
>
> I have an algorithm in mind but it requires lots of custom code and I'm wondering if there's a clever way to do it with built-in functions.  Thanks.
>

Hi,

the fastest way I was able to find is about four times faster than the
naive approach

Flatten[Position[x, Alternatives @@ Intersection[x, y], 1]]

Dropping successively the irrelevant parts of the huge list x, searching
becomes faster:

Reap[
Fold[
Drop[#1, Sow[LengthWhile[#1, Function[x0, x0 <= #2]]]] &,
x, Intersection[x, y]
]
][[2, 1]] // Accumulate

I tried patterns and compilation; to no avail (see [1]).

Cheers,
Peter

[1] https://dl.dropbox.com/u/3030567/Mathematica/getpositions.nb

```

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