Re: FindRoot with a vector of unknowns

*To*: mathgroup at smc.vnet.net*Subject*: [mg125055] Re: FindRoot with a vector of unknowns*From*: Bob Hanlon <hanlonr357 at gmail.com>*Date*: Mon, 20 Feb 2012 02:45:20 -0500 (EST)*Delivered-to*: l-mathgroup@mail-archive0.wolfram.com*References*: <201202191128.GAA15560@smc.vnet.net>

Solve[#, x][[1]] & /@ Thread[x - {1, 2, 3} == {0, 0, 0}] {{x -> 1}, {x -> 2}, {x -> 3}} (Reduce[#, x] // ToRules) & /@ Thread[x - {1, 2, 3} == {0, 0, 0}] {{x -> 1}, {x -> 2}, {x -> 3}} FindRoot[#, {x, 1}] & /@ Thread[x - {1, 2, 3} == {0, 0, 0}] {{x -> 1.}, {x -> 2.}, {x -> 3.}} Bob Hanlon On Sun, Feb 19, 2012 at 6:28 AM, Sam Takoy <sam.takoy at yahoo.com> wrote: > Hi, > > Is there an elegant way to implement what I am trying to do here, that > is solve for a vector of unknowns: > > FindRoot[x - {1, 2, 3} == {0, 0, 0}, {x, {1, 1, 1}}] > > I can do this writing a loop, but hoping for a "vectorized" solution. > > Thanks, > > Sam >

**References**:**FindRoot with a vector of unknowns***From:*Sam Takoy <sam.takoy@yahoo.com>