Re: How to change individual colors of an image

• To: mathgroup at smc.vnet.net
• Subject: [mg125079] Re: How to change individual colors of an image
• From: Szabolcs Horvát <szhorvat at gmail.com>
• Date: Mon, 20 Feb 2012 02:53:42 -0500 (EST)
• Delivered-to: l-mathgroup@mail-archive0.wolfram.com
• References: <jho1tn\$5r0\$1@smc.vnet.net>

```On 2/18/2012 1:26 PM, Alexei Boulbitch wrote:
> Dear community,
>
>
>
> My question relates to the work with an image. There are plenty of operators influencing the image as a whole. May be I have missed, but I could not find, if it is possible to work with all pixels possessing a given colour, (or may be, a group of colours close to one another) in  such  a way that this colour changes to another that is desired one.
>
>
>
> To be precise, below I paste a full form of a small piece of an image with white (or light gray), black and red fragments. Is it possible to say, change black into blue? Light gray into yellow?
>
>
>
> To see the image please copy-paste the 30 lists given below along with two code lines (combining them into the image) into Mathematica and execute:
>
>
>

Dear Alexei,

A simple way to send complex expressions is using Compress/Uncompress
(see at the end of this message).

There are several ways to achieve what you need, but I am going to show
a more general way here, called masking.  This can be generalized to
many problems.

Suppose the image is stored in variable img

Let's first find all pixels that have colour {138, 138, 138}/255

mask = Binarize[img, # == {138, 138, 138}/255 &]

Alternatively use colours that are close to this shade of grey:

mask = Binarize[img, Norm[# - {138, 138, 138}/255] < 0.05 &]

Then change the image in the matching region green (i.e. colour {0,1,0}:

If you have Mathematica 7, you could use ImageApply directly:

ImageApply[If[# == {138, 138, 138}/255, {0, 1, 0}, #] &, img]

------------------->8------------------

This is the image in a more compact and ASCII-only format:

img = Uncompress@
"1:eJzt189r03AYx/GQ/pisddY1zKgz61Zk3qzCGN5cN5QdJjQVVCi6VLLNWt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"

-------------------8<------------------

This is how it was generated:

wrap[string_, width_] :=
StringJoin@
Riffle[Partition[Characters[string], width, width, {1, 1}, {}],
"\n"]

wrap[Compress[img], 60]

--
Szabolcs Horvát
Visit Mathematica.SE:  http://mathematica.stackexchange.com/

```

• Prev by Date: Re: How best to implement a hash table in Mathematica
• Next by Date: Re: Iterative solution to a transcendental equation.
• Previous by thread: How to change individual colors of an image
• Next by thread: Interrupt a block