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Re: Sorting coefficients
*To*: mathgroup at smc.vnet.net
*Subject*: [mg124041] Re: Sorting coefficients
*From*: Bob Hanlon <hanlonr357 at gmail.com>
*Date*: Sat, 7 Jan 2012 05:16:41 -0500 (EST)
*Delivered-to*: l-mathgroup@mail-archive0.wolfram.com
*References*: <201201060914.EAA26796@smc.vnet.net>
pts = Prepend[
Table[{Re, Im}[E^(k (2 \[Pi])/6 I)] //
Through, {k, 0, 5}], {0, 0}];
n = 1; Graphics[Text[n++, #] & /@ pts]
To sort by layer and then within layer
order2 = SortBy[pts,
{N[Last[#]], N[First[#]]} &];
Note that the coordinates need to be converted to Reals for the
canonical order to be the same as numerical order.
n = 1; Graphics[Text[n++, #] & /@ order2]
Sorting from lower left to upper right
order3 = SortBy[pts,
{Norm[N[#] - order2[[1]]], Last[N[#]]} &];
n = 1; Graphics[Text[n++, #] & /@ order3]
Bob Hanlon
On Fri, Jan 6, 2012 at 4:14 AM, Chris Young <cy56 at comcast.net> wrote:
> I'm trying to get my points sorted first by rows first. But I'm having
> trouble figuring out how to do the kind of double sorting I need with
> Sort. SortBy seems very hard to figure out and I'm not sure if it's
> what I need here.
>
> I've just got a hexagonal layout of point coordinates, with another one
> on the origin, and I'm trying to sort everything from lower left to
> upper right. I.e., the usual ordering of going through the bottom row
> from left to right, then through the middle row from left to right, etc.
>
> Any help appreciated.
>
> Chris Young
> cy56 at comcast.net
>
>
> In[1043]:= Prepend[
> Table[{Re, Im}[ E^(k (2 \[Pi])/6 I)] // Through, {k, 0, 5}], {0, 0}]
>
> Out[1043]= {{0, 0}, {1, 0}, {1/2, Sqrt[3]/2}, {-(1/2), Sqrt[3]/
> 2}, {-1, 0}, {-(1/2), -(Sqrt[3]/2)}, {1/2, -(Sqrt[3]/2)}}
>
> In[1046]:= Sort[%1043, #1[[2]] < #2[[2]] &]
>
> Out[1046]= {{1/2, -(Sqrt[3]/2)}, {-(1/2), -(Sqrt[3]/2)}, {-1, 0}, {1,
> 0}, {0, 0}, {-(1/2), Sqrt[3]/2}, {1/2, Sqrt[3]/2}}
>
> In[1073]:= Sort[%1046, #1[[2]] < #2[[2]] &]
>
> Out[1073]= {{-(1/2), -(Sqrt[3]/2)}, {1/2, -(Sqrt[3]/2)}, {0, 0}, {1,
> 0}, {-1, 0}, {1/2, Sqrt[3]/2}, {-(1/2), Sqrt[3]/2}}
>
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