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Re: Is there any efficient easy way to compare two lists with the same length with Mathematica?

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  • Subject: [mg124410] Re: Is there any efficient easy way to compare two lists with the same length with Mathematica?
  • From: DrMajorBob <btreat1 at austin.rr.com>
  • Date: Thu, 19 Jan 2012 05:06:27 -0500 (EST)
  • Delivered-to: l-mathgroup@mail-archive0.wolfram.com

a == b and a === b evaluate before Thread has a chance to act. The others  
do not.

a < b
a > b
a == b
a === b

{1, 2, 3} < {3, 2, 1}

{1, 2, 3} > {3, 2, 1}

False

False

Bobby

On Wed, 18 Jan 2012 04:58:07 -0600, James Stein <mathgroup at stein.org>  
wrote:

> I learned something from the answer(s) on this thread, leading to a
> question of my own: Why do 'Equal' and 'SameQ' respond differently
> from  'Greater' and 'Less' ? e.g.:
>
> a = {1, 2, 3};
> b = {3, 2, 1};
> Thread[a < b]
> Thread[a == b]
> Thread[a === b]
> Thread[b < a]
>
> On Tue, Jan 17, 2012 at 4:01 AM, Bill Rowe <readnews at sbcglobal.net>  
> wrote:
>
>> On 1/17/12 at 3:34 AM, aoirex at gmail.com (Rex) wrote:
>>
>> >Given two lists `A={a1,a2,a3,...an}` and `B={b1,b2,b3,...bn}`, I
>> >would say `A>=B` if and only if all `ai>=bi`.
>>
>> >There is a built-in logical comparison of two lists, `A==B`, but no
>> >`A>B`. Do we need to compare each element like this
>>
>> >And@@Table[A[[i]]>=B[[i]],{i,n}]
>>
>> I think you do need to do an element by element comparison. But
>> you don't need to specifically select each element using Part as
>> you are doing. That is:
>>
>> In[13]:= {a, b} = RandomInteger[100, {2, 5}];
>> And @@ Thread[a > b]
>>
>> Out[14]= False
>>
>> In[15]:= c = RandomInteger[{150, 200}, 5];
>> And @@ Thread[c > a]
>>
>> Out[16]= True
>>
>>
>>


-- 
DrMajorBob at yahoo.com



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