Re: Simplification de formule/ Simplification of formula
- To: mathgroup at smc.vnet.net
- Subject: [mg124434] Re: Simplification de formule/ Simplification of formula
- From: DrMajorBob <btreat1 at austin.rr.com>
- Date: Thu, 19 Jan 2012 05:14:48 -0500 (EST)
- Delivered-to: l-mathgroup@mail-archive0.wolfram.com
- References: <201201181104.GAA16719@smc.vnet.net>
- Reply-to: drmajorbob at yahoo.com
-((DK Pv2 Cos[a2 - alpha3] Cos[aV2] Sin[ a2 - aV2])/(DK Cos[a2 - alpha3] - KF Sin[a2 - alpha3])) + (KF Pv2 Cos[aV2] Sin[a2 - alpha3] Sin[ a2 - aV2])/(DK Cos[a2 - alpha3] - KF Sin[a2 - alpha3]) - (DG3 P3 Sin[alpha3] Sin[ a2 - aV2])/(DK Cos[a2 - alpha3] - KF Sin[a2 - alpha3]) - (DK FV2 Pv2 Cos[a2 - alpha3] Cos[ a2 - aV2] Sin[ aV2])/(L2 (DK Cos[a2 - alpha3] - KF Sin[a2 - alpha3])) + (FV2 KF Pv2 Cos[a2 - aV2] Sin[ a2 - alpha3] Sin[ aV2])/(L2 (DK Cos[a2 - alpha3] - KF Sin[a2 - alpha3])) - (KF Pv2 Cos[a2 - alpha3] Sin[ a2 - aV2] Sin[aV2])/(DK Cos[a2 - alpha3] - KF Sin[a2 - alpha3]) + (FV2 KF Pv2 Cos[a2 - alpha3] Sin[ a2 - aV2] Sin[ aV2])/(L2 (DK Cos[a2 - alpha3] - KF Sin[a2 - alpha3])) - (DK Pv2 Sin[a2 - alpha3] Sin[ a2 - aV2] Sin[aV2])/(DK Cos[a2 - alpha3] - KF Sin[a2 - alpha3]) + (DK FV2 Pv2 Sin[a2 - alpha3] Sin[ a2 - aV2] Sin[ aV2])/(L2 (DK Cos[a2 - alpha3] - KF Sin[a2 - alpha3])) // TrigExpand // FullSimplify -(FV2 KF Pv2 Cos[2 a2 - alpha3] - KF L2 Pv2 Cos[alpha3] - FV2 KF Pv2 Cos[2 a2 - alpha3 - 2 aV2] + KF L2 Pv2 Cos[2 a2 - alpha3 - 2 aV2] + DG3 L2 P3 Cos[a2 - alpha3 - aV2] - DG3 L2 P3 Cos[a2 + alpha3 - aV2] + DK FV2 Pv2 Sin[2 a2 - alpha3] + DK L2 Pv2 Sin[alpha3] + DK (-FV2 + L2) Pv2 Sin[ 2 a2 - alpha3 - 2 aV2])/(2 L2 (DK Cos[a2 - alpha3] - KF Sin[a2 - alpha3])) Bobby On Wed, 18 Jan 2012 05:04:01 -0600, Nicolas Simon <nicodumonastal at gmail.com> wrote: > > Hi ! > > I want to simplify this formula : > > -((DK Pv2 Cos[a2 - alpha3] Cos[aV2] Sin[a2 - aV2])/( > DK Cos[a2 - alpha3] - KF Sin[a2 - alpha3])) + ( > KF Pv2 Cos[aV2] Sin[a2 - alpha3] Sin[a2 - aV2])/( > DK Cos[a2 - alpha3] - KF Sin[a2 - alpha3]) - ( > DG3 P3 Sin[alpha3] Sin[a2 - aV2])/( > DK Cos[a2 - alpha3] - KF Sin[a2 - alpha3]) - ( > DK FV2 Pv2 Cos[a2 - alpha3] Cos[a2 - aV2] Sin[aV2])/( > L2 (DK Cos[a2 - alpha3] - KF Sin[a2 - alpha3])) + ( > FV2 KF Pv2 Cos[a2 - aV2] Sin[a2 - alpha3] Sin[aV2])/( > L2 (DK Cos[a2 - alpha3] - KF Sin[a2 - alpha3])) - ( > KF Pv2 Cos[a2 - alpha3] Sin[a2 - aV2] Sin[aV2])/( > DK Cos[a2 - alpha3] - KF Sin[a2 - alpha3]) + ( > FV2 KF Pv2 Cos[a2 - alpha3] Sin[a2 - aV2] Sin[aV2])/( > L2 (DK Cos[a2 - alpha3] - KF Sin[a2 - alpha3])) - ( > DK Pv2 Sin[a2 - alpha3] Sin[a2 - aV2] Sin[aV2])/( > DK Cos[a2 - alpha3] - KF Sin[a2 - alpha3]) + ( > DK FV2 Pv2 Sin[a2 - alpha3] Sin[a2 - aV2] Sin[aV2])/( > L2 (DK Cos[a2 - alpha3] - KF Sin[a2 - alpha3])). > > By manually regrouping the terms, the denominator disappears for a > large number of fraction but I'm not able to reproduce this result > with Simplify or others Mathematica tools to handle formula. Any > suggestion of how I could do that with Mathematica ? > Thank you for your help ! > > > > > > > > > > Bonjour, > > Je souhaite simplifier cette formule : > > -((DK Pv2 Cos[a2 - alpha3] Cos[aV2] Sin[a2 - aV2])/( > DK Cos[a2 - alpha3] - KF Sin[a2 - alpha3])) + ( > KF Pv2 Cos[aV2] Sin[a2 - alpha3] Sin[a2 - aV2])/( > DK Cos[a2 - alpha3] - KF Sin[a2 - alpha3]) - ( > DG3 P3 Sin[alpha3] Sin[a2 - aV2])/( > DK Cos[a2 - alpha3] - KF Sin[a2 - alpha3]) - ( > DK FV2 Pv2 Cos[a2 - alpha3] Cos[a2 - aV2] Sin[aV2])/( > L2 (DK Cos[a2 - alpha3] - KF Sin[a2 - alpha3])) + ( > FV2 KF Pv2 Cos[a2 - aV2] Sin[a2 - alpha3] Sin[aV2])/( > L2 (DK Cos[a2 - alpha3] - KF Sin[a2 - alpha3])) - ( > KF Pv2 Cos[a2 - alpha3] Sin[a2 - aV2] Sin[aV2])/( > DK Cos[a2 - alpha3] - KF Sin[a2 - alpha3]) + ( > FV2 KF Pv2 Cos[a2 - alpha3] Sin[a2 - aV2] Sin[aV2])/( > L2 (DK Cos[a2 - alpha3] - KF Sin[a2 - alpha3])) - ( > DK Pv2 Sin[a2 - alpha3] Sin[a2 - aV2] Sin[aV2])/( > DK Cos[a2 - alpha3] - KF Sin[a2 - alpha3]) + ( > DK FV2 Pv2 Sin[a2 - alpha3] Sin[a2 - aV2] Sin[aV2])/( > L2 (DK Cos[a2 - alpha3] - KF Sin[a2 - alpha3])). > > En regroupant les bons termes le d=E9nominateur se simplifie pour un > grand nombres de fractions mais je n'arrive pas a ce r=E9sultat avec les > outils de simplification (FullSimplify ou Simplify) ou les outils de > manipulations de formule. Est ce que vous auriez une id=E9e de comment > faire comme pr=E9ciser certains "assumption" dans Simplify ? > Merci de votre aide. > -- DrMajorBob at yahoo.com
- References:
- Simplification de formule/ Simplification of formula
- From: Nicolas Simon <nicodumonastal@gmail.com>
- Simplification de formule/ Simplification of formula