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Re: Can anyone see a faster way to compute quantities for a pair or large matrices?

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  • Subject: [mg127428] Re: Can anyone see a faster way to compute quantities for a pair or large matrices?
  • From: "andre.robin3" <andre.robin281 at orange.fr>
  • Date: Tue, 24 Jul 2012 04:14:58 -0400 (EDT)
  • Delivered-to: l-mathgroup@mail-archive0.wolfram.com
  • Delivered-to: mathgroup-newout@smc.vnet.net
  • Delivered-to: mathgroup-newsend@smc.vnet.net
  • References: <juim0j$k9a$1@smc.vnet.net>

Your problem is a good candidate for parallel computing.

It can be :

1) multi-kernel computing (with Mathematica 7 or Mathematica 8). It's easy to implement.
  Of course, it needs a multi-core machine.

2) GPGPU computing (with Mathmatica 8)
  It needs a Graphic Card with CUDA or OPENCL capabilities.

I can try 1) or 2) with CUDA.

Are you interested ?



"W Craig Carter" <ccarter at MIT.EDU> a écrit dans le message de news: 
juim0j$k9a$1 at smc.vnet.net...
>
> Hello,
> I am computing the gradient on a grid, then computing the gradient's
> angle, and its magnitude. The computations below are the bottleneck for
> a longer bit of code.  I would be grateful for any insights on how to
> speed these up.
>
> (*
> Let gradfield be the gradient that I have computed and placed in two 
> matrices. Here I will just use random numbers as a proxy:
> *)
>
> (*i.e., df/dx, df/dy*)
> gradfield =  { RandomReal[{-1, 1}, {256, 256}], RandomReal[{-1, 1}, {256, 
> 256}]};
>
> (*my gradients has many zeroes, so I need to handle these*)
>
> SetAttributes[myArcTan, {Listable, NumericFunction}];
> myArcTan[0.0, 0.0] = 0.0;
> myArcTan[x_, y_] := ArcTan[x, y]
>
>
> (*the angles, this is slow*)
> psiField = MapThread[myArcTan, gradfield, 2];
>
> (*the magnitudes, this is slower*)
> magfield =  MapThread[Norm[{#}] &, gradfield, 2];
>
>
> (*examples*)
> Do[psiField = MapThread[myArcTan, gradfield, 2], {100}] // Timing
> Do[magfield =  MapThread[Norm[{#}] &, gradfield, 2], {100}] // Timing
>
> W Craig Carter
> Professor of Materials Science, MIT 





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