MathGroup Archive 2012

[Date Index] [Thread Index] [Author Index]

Search the Archive

Subject: Re: Using Fit to interpolate data

I like Bill Rowe's:

In[12]:= params=FindFit[fiberDataDensitiesFeierabend, a Exp[b
x], {a, b}, x]

Out[12]= {a->2.06978*10^6,b->-1.61827}


Plot[a Exp[b x] /. params, {x, 7, 16.5},
  Epilog -> {PointSize[.02], Point[fiberDataDensitiesFeierabend]}]

Here is another alternative of the same thing.

In[]:= f = NonlinearModelFit[fiberDataDensitiesFeierabend, a Exp[b x], {a, b}, x]
Out[]:= FittedModel[2.06978x10^6 * e^(-1.61827 * x)   ]

In[]:= Plot[f[x],{x,7,16.5},Epilog->{PointSize[.02],Point[fiberDataDensitiesFeierabend]}]
Out[]:= (same result)

In[]:= f["FitResiduals"]
Out[]:=   {-0.0000117777,0.0474942,0.0884309,0.128468,-0.038007,0.00348739}

In[]:= f["ParameterConfidenceIntervals"]
Out[]:= {{1.11329*10^6,3.02627*10^6},{-1.68272,-1.55381}}

I really like the FitResiduals you can use with object returned by NonlinearModelFit[].  There is also EstimatedVariance, BestFit.  Just saying, you might want to look into it.  There is an excellent youtube video.

Paul McHale  |  Electrical Engineer, Energetics Systems  |  Excelitas Technologies Corp.
Phone:   +1 937.865.3004   |   Fax:  +1 937.865.5170   |   Mobile:   +1 937.371.2828
1100 Vanguard Blvd, Miamisburg, Ohio 45342-0312 USA
Paul.McHale at

Please consider the environment before printing this e-mail.
This email message and any attachments are confidential and proprietary to Excelitas Technologies Corp. If you are not the intended recipient of this message, please inform the sender by replying to this email or sending a message to the sender and destroy the message and any attachments.
Thank you

  • Prev by Date: Re: Putting a Test or Condition on the Right-Hand Side of a Function
  • Next by Date: Re: How to relate two functions
  • Previous by thread: Re: Heat Equation on a surface sphere using NDSolve?
  • Next by thread: AlgebraicRules