Re: Cool example with ContourPlot+EvaluationMonitor
- To: mathgroup at smc.vnet.net
- Subject: [mg125579] Re: Cool example with ContourPlot+EvaluationMonitor
- From: Ralph Dratman <ralph.dratman at gmail.com>
- Date: Mon, 19 Mar 2012 05:01:07 -0500 (EST)
- Delivered-to: l-mathgroup@mail-archive0.wolfram.com
- References: <jk1fpb$4v0$1@smc.vnet.net>
Could one of you please explain a little more? I think I get the general idea about putting together the plot of an implicit function by a sort of scanning process, but I don't understand the details. Thank you. Ralph On Sun, Mar 18, 2012 at 3:43 AM, Murta <rodrigomurtax at gmail.com> wrote: > Nice!.. I played with the code and made it shorter. > It's the same thing. > > Dynamic[ > ListPlot[data, Frame -> True, AspectRatio -> 1, PlotStyle -> Blue, > PlotRange -> {{-1.6, 1.6}, {-1.6, 1.6}}, Epilog -> Circle[{0, 0}]]] > data = {}; freeze = 0.01 > > ContourPlot[x^2 + y^2 == 1, {x, -1.5, 1.5}, {y, -1.5, 1.5}, > EvaluationMonitor :> (AppendTo[data, {x, y}]; Pause[freeze])] > > []'s > Murta > On Mar 17, 4:51 am, psycho_dad <s.nesse... at gmail.com> wrote: >> The following example shows in real-time (sort of) how ContourPlot calculates a contour (in this example a unit circle): >> >> f[x_, y_, freeze_] := (Pause[freeze]; (x^2 + y^2)) >> data = {}; freeze = 0.04; >> Dynamic[ListPlot[data, Frame -> True, AspectRatio -> 1, >> PlotStyle -> Blue, PlotRange -> {{-1.6, 1.6}, {-1.6, 1.6}}, >> Epilog -> Circle[{0, 0}]]] >> ContourPlot[f[x, y, freeze] == 1, {x, -1.5, 1.5}, {y, -1.5, 1.5}, >> EvaluationMonitor :> AppendTo[data, {x, y}]]; >> >> Initially I just wanted to get all the points from ContourPlot, but then it dawned on me that using Dynamic I could do that in real time! I hope you like it :D >> >> Cheers >> >> PS Change the parameter freeze (set to 0.04 secs) to make the animation slower or faster. >> PPS This is so cool, I just knew I had to share it! > >
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