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Derivatives in replacement rules
- To: mathgroup at smc.vnet.net
- Subject: [mg125733] Derivatives in replacement rules
- From: Yi Wang <tririverwangyi at gmail.com>
- Date: Fri, 30 Mar 2012 04:36:42 -0500 (EST)
- Delivered-to: l-mathgroup@mail-archive0.wolfram.com
Hi, all,
When I am using the following replacement rule:
b[t] c[t] a'[t] /. b_ a_'[t] -> D[b, t]
I would expect to get D[b[t]c[t], t] = b'[t]c[t] + c'[t]b[t]. However,
I got 0 actually. To debug, when I set
b[t] c[t] a'[t] /. b_ a_'[t] -> b
I get b[t] c[t]. Thus pattern matching works and it appears D[b,t]
should be non-zero.
Any ideas how I can get D[b[t]c[t], t] in the above pattern
replacement? Thanks!
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