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MathGroup Archive 2012

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Re: New to Mathematica

  • To: mathgroup at smc.vnet.net
  • Subject: [mg126389] Re: New to Mathematica
  • From: David Bailey <dave at removedbailey.co.uk>
  • Date: Sun, 6 May 2012 03:24:34 -0400 (EDT)
  • Delivered-to: l-mathgroup@mail-archive0.wolfram.com
  • References: <jntga4$2c$1@smc.vnet.net> <jo2nld$mds$1@smc.vnet.net>

On 05/05/2012 09:16, J.Jack.J. wrote:
> On May 3, 9:40 am, "J.Jack.J."<jack.j.jep... at googlemail.com>  wrote:
>> Hi,
>>
>>   I have just downloaded my free trial version of Mathematica.
>>   I only need it for one thing (as yet, anyway), and I wonder whether
>> someone can help me in step-by-step fashion to get what I want. I need
>> the solution to the following (I might make amendments to the values):
>>
>> "For any integer k, let r(k) be x such that
>>
>> (x/ln(x))*(1 + 1/ln(x)) = 108.2 + k)
>>
>> product (k = 0 to 3000) (1-1/r(k))"
>>
>> With many thanks in advance.
>
> Can nobody help me with this? Just for a Newbie?
> As most will realise, the first lines define my function and the
> product (k = 0 to 3000) (1-1/r(k))
> is my desired calculation. I need to know what inputs to use.
>
> With thanks in advance.
>

If you press F1, you will enter the help system. Once there, you could 
try looking up log and product. The examples will give you the basics of 
Mathematica syntax, and you can cut and paste them into your notebook, 
and alter them as desired.

David Bailey
http://www.dbaileyconsultancy.co.uk



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