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Re: Partition string into length n chunks


A single argument function doesn't need an explicit argument when mapped

chunk[s_String, n_Integer] :=
 StringJoin /@ Partition[Characters[s], n]


Bob Hanlon


On Thu, May 17, 2012 at 4:11 AM, David G <daggillies at gmail.com> wrote:
> I am sure this is trivially simple, but how do I partition a string into non-overlapping length n chunks? The best I could come up with is chunk[s_, n_] := StringJoin[#] & /@ Partition[Characters[s], n] but this seems overly long-winded.
>



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