Re: Question about ColorFunction

*To*: mathgroup at smc.vnet.net*Subject*: [mg126608] Re: Question about ColorFunction*From*: Bob Hanlon <hanlonr357 at gmail.com>*Date*: Thu, 24 May 2012 03:32:01 -0400 (EDT)*Delivered-to*: l-mathgroup@mail-archive0.wolfram.com*References*: <201205230729.DAA04974@smc.vnet.net>

"With the usual default setting ColorFunctionScaling->True, all arguments supplied to func are scaled to lie in the range 0 to 1." In your first example, #1 and #2 are each scaled before being fed to Sin[#1 + #2]] & so the argument of the Sin is in the interval {0, 2}. In your second example, the argument of Hue[#3] & is in the interval {0, 1}. The plots would be identical if you used ColorFunctionScaling -> False in each. Bob Hanlon On Wed, May 23, 2012 at 3:29 AM, Jee Lou <ywdr1987 at gmail.com> wrote: > Anyone explain to me how ColorFunction works? Why Plot3D[Sin[x + y], {x, 0, 3}, {y, 0, 3}, ColorFunction -> (Hue[Sin[#1 + #2]] &)] and Plot3D[Sin[x + y], {x, 0, 3}, {y, 0, 3}, ColorFunction -> (Hue[#3] &)] return different color distributions? >

**References**:**Question about ColorFunction***From:*Jee Lou <ywdr1987@gmail.com>